A) \[\text{10440 c}{{\text{m}}^{\text{3}}}\text{, 91250 g}\]
B) \[\text{13440 c}{{\text{m}}^{\text{3}}}\text{, 90000 g}\]
C) \[\text{11440 c}{{\text{m}}^{\text{3}}}\text{, 91520 g}\]
D) \[\text{12440 c}{{\text{m}}^{\text{3}}}\text{, 91550 g}\]
Correct Answer: C
Solution :
Thickness of the hollow metallic cylinder = 2 cm Height of the cylinder = 70 cm Let R and r be the outer and inner radii of the cylinder \[\therefore R=14cm\] and \[r-14-2=12cm\] Volume of the metal used \[=\pi h({{R}^{2}}-{{r}^{2}})\] \[=\frac{22}{7}\times 70({{14}^{2}}-{{12}^{2}})=220\times 52=11440\] If the metal weighs 8g per \[c{{m}^{3}}\], so \[11440c{{m}^{3}}\]. Metal weigh\[=11440\times 8=91.520g\]
You need to login to perform this action.
You will be redirected in
3 sec
