A) Their areas are equal
B) The area of the circle is greater
C) The area of the square is greater
D) None of the above
Correct Answer: B
Solution :
Let the length of a side of square be a, and radius of the circle is r. Since square and circle have the same perimeter. \[\therefore \] \[2\pi \,\,r=4a\] or \[r=\frac{2a}{\pi }\]\[\therefore \] \[\frac{Area\,of\,the\,circle}{Area\,of\,the\,square}=\frac{\pi {{r}^{2}}}{{{a}^{2}}}=\frac{\pi .\frac{4{{a}^{2}}}{{{\pi }^{2}}}}{{{a}^{2}}}=\frac{4}{\pi }>1\] Hence, area of the circle is greater than area of the square.
You need to login to perform this action.
You will be redirected in
3 sec
