A) Rs.90
B) Rs.97
C) Rs.110
D) Rs.95
Correct Answer: C
Solution :
Radius of tower\[=\frac{5}{2}m\] Height of tower \[\text{= 14 m}\] \[\therefore \] Curved surface area \[=2\pi rh\] \[=2\times \frac{22}{7}\times \frac{5}{2}\times 14=220{{m}^{2}}\] \[\therefore \]Cost of white washing the curved surface area \[=220\times \frac{50}{100}=Rs.110\]
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