A) \[\frac{30}{\pi }\]
B) \[60\pi \]
C) \[\frac{15}{\pi }\]
D) \[\frac{30}{{{\pi }^{2}}}\]
Correct Answer: C
Solution :
Surface area of sphere of radius \[210c{{m}^{2}}\] After increase of P% the radius becomes \[213c{{m}^{2}}\] Hence new surface area\[224c{{m}^{2}}\] \[216c{{m}^{2}}\] Percentage increase \[\frac{100\sqrt{2}}{\pi }cm\] \[\frac{50\sqrt{2}}{\pi }cm\] \[\frac{100}{\pi }cm\]
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