A) 25%
B) 55%
C) 40.5%
D) 56.25%
Correct Answer: D
Solution :
\[x=\] Side before increase \[{{x}^{2}}=\]Area before increase \[\frac{125x}{100}=\]Side after increase \[\frac{25{{x}^{2}}}{16}=\]Area after increase Increase in area= \[\frac{\frac{25{{x}^{2}}-16{{x}^{2}}}{16}\times 100%}{{{x}^{2}}}\] \[=\frac{9{{x}^{2}}}{16{{x}^{2}}}\times 100=\frac{225}{4}=56.25%\]
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