A) \[\left( 2P+\frac{{{P}^{2}}}{100} \right)%\]
B) \[\frac{{{P}^{2}}}{2}%\]
C) \[62\frac{6}{7}sq.cm\]
D) \[57\frac{3}{4}sq.cm\]
Correct Answer: A
Solution :
Let the radii of the spheres be \[\Delta ABC\] and \[\Delta ABC=\frac{1}{2}\times BC\times AB\]. Then, \[ABCD=AB\times BC=l\times b\] or \[=l+b+l+b\] or \[=2l+2b\] Let \[=2(l+b)\] and \[=\sqrt{{{l}^{2}}+{{b}^{2}}}\] Then \[a={{a}^{2}}\]or \[AC=\sqrt{{{a}^{2}}+{{b}^{2}}}=\sqrt{2{{a}^{2}}}=a\sqrt{2}=\sqrt{2}\times \]or \[\Delta ABD\] \[\Delta BCD\] \[=\left( \frac{1}{2}\times BD\times AL \right)+\left( \frac{1}{2}\times BD\times CM \right)\] and \[=\frac{1}{2}\times BD\times (AL+CM)\] units \[=b\times h\] Difference of their surface areas \[=\frac{1}{2}\times \] \[=\frac{1}{2}{{d}_{1}}\times {{d}_{2}}\] sq units.
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