A) \[88\pi sq.units\]
B) \[48\pi sq.units\]
C) \[1:\sqrt{3}\]
D) \[50%\]
Correct Answer: A
Solution :
Given that \[\Delta AOB\]We have, i.e. \[Arc\frac{\theta }{{{360}^{o}}}\times 2\pi r,\] \[\theta \] \[(\pi =3.14)\] \[={{4}^{2}}-4\times \frac{{{90}^{o}}}{{{360}^{o}}}\times \pi \times {{2}^{2}}=16-4\times \frac{1}{4}\times 3.14\times 4\] \[=16-3.14\times 4=16-12.56=3.44c{{m}^{2}}.\]
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