A) \[{{\text{r}}^{2}}(\pi -2)\]
B) \[\text{2}{{\text{r}}^{2}}(2-\pi )\]
C) \[\pi \text{(}{{\text{r}}^{2}}-2)\]
D) \[8{{r}^{2}}-8r\]
Correct Answer: A
Solution :
Radius of circle \[=r\therefore Area=\pi {{r}^{2}}\] Now, diameter of circle is equal to diagonal of square RSTV So, length of diagonal \[=2r\] \[\Rightarrow \text{Side of the square=}\frac{2r}{\sqrt{2}}=\sqrt{2}r\] \[\therefore \]Area of square \[={{(side)}^{2}}={{(\sqrt{2}r)}^{2}}=2{{r}^{2}}\] \[\Rightarrow \]Area of shaded part \[=\pi {{r}^{2}}-2{{r}^{2}}=(\pi -2){{r}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
