A) \[1,080\,{{m}^{2}}\]
B) \[640\,{{m}^{2}}\]
C) \[1,620\,\,{{m}^{2}}\]
D) \[2,160\,{{m}^{2}}\]
Correct Answer: A
Solution :
Let breadth = b m Then, length \[=\frac{6}{5}b\,m\] \[\because \] Perimeter = 132 \[\therefore \] \[2(b+\frac{6}{5}b)=132\] \[210c{{m}^{2}}\] \[213c{{m}^{2}}\] Hence, length \[224c{{m}^{2}}\] And area \[216c{{m}^{2}}\] \[\frac{100\sqrt{2}}{\pi }cm\]
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