A) \[32.2\,c{{m}^{2}}\]
B) \[24.4\,c{{m}^{2}}\]
C) \[35.4\,c{{m}^{2}}\]
D) \[31.4\,c{{m}^{2}}\]
Correct Answer: D
Solution :
Area of region II \[=\frac{22}{7}(4)-\frac{22}{7}(1)\] \[=\frac{66}{7}c{{m}^{2}}\] Area of region\[\text{I}=\frac{22}{7}16-\frac{22}{7}(9)\] \[=\frac{154}{7}=22\,c{{m}^{2}}\] \[\therefore \]Required area = Area of region I + Area of region II \[=\frac{154}{7}=\frac{66}{7}=31.4\,c{{m}^{2}}\].You need to login to perform this action.
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