A) \[6\frac{1}{2}cm\]
B) \[6cm\]
C) \[6\frac{2}{3}cm\]
D) None of these
Correct Answer: C
Solution :
Here, we equalize the areas, i.e., \[AB\times DL=BC\times DM\] \[18\times DL=12\times 10\] \[DL=\frac{12\times 10}{18}=\frac{20}{3}=6\frac{2}{3}cm.\]You need to login to perform this action.
You will be redirected in
3 sec