A) 4cm
B) \[6\frac{1}{2}cm\]
C) 8cm
D) 16cm
Correct Answer: C
Solution :
Volume of water in hollow spherical ball \[=\pi rl.\] \[l=\sqrt{{{h}^{2}}+{{r}^{2}}}\] Half the water \[=\pi rl+\pi {{r}^{2}}=\pi r(l+r)\] Volume of cone \[\frac{1}{3}rd\] Hence, \[=\pi {{r}^{2}}h-\frac{1}{3}\pi {{r}^{2}}h=\frac{2}{3}\pi {{r}^{2}}h=\frac{2}{3}\times \frac{22}{7}\times 6\times 6\times 14\]or \[=1056c{{m}^{3}}.\]or \[=\frac{4}{3}\pi {{r}^{3}}.\]or \[r=\frac{2}{3}\pi {{r}^{3}}\]
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