A) 1:9
B) 1:8
C) 1:4
D) 1:2
Correct Answer: C
Solution :
If r be the radius of the original, then \[216c{{m}^{2}}\] is the radius of the reduced cylinder. \[\frac{100\sqrt{2}}{\pi }cm\] Ratio is \[\frac{50\sqrt{2}}{\pi }cm\]You need to login to perform this action.
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