A) 1 : 1
B) 1 : 2
C) 1 : 3
D) 3 :1
Correct Answer: D
Solution :
\[\Delta \,ABC-\Delta \,DEF\] \[\frac{Area\,of\,\Delta \,ABC}{Area\,of\,\Delta \,DEF}=\frac{{{(BC)}^{2}}}{{{(EF)}^{2}}}=\frac{{{(2a)}^{2}}}{{{a}^{2}}}=\frac{4}{1}\] \[\frac{Area\,of\,\Delta \,ABC-Area\,of\,\Delta \,DEF}{Area\,of\,\Delta \,DEF}=\frac{4-1}{1}=\frac{3}{1}\] \[\therefore \] Area of path : Area of flower bed \[=3:1\].You need to login to perform this action.
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