A) 135
B) 140
C) 125
D) 120
Correct Answer: A
Solution :
Let the length and breadth be \[2x\] and \[3x\] respectively. Then, floor area \[=6{{x}^{2}}\,sq.m.\] Cost of flooring at the rate of \[Rs.\,4.00\,per\,{{m}^{2}}\] \[=Rs.\,216\] \[\therefore \] \[6{{x}^{2}}\times 4=216\] or \[{{x}^{2}}=9\] or \[x=3\] \[\therefore \] Length \[=3x=9m\] Breadth \[=2x=6m\] and Height \[=\frac{1}{2}\times Length=4.5m\] \[\therefore \] Area of four walls \[=2[length\times height+breadth\times heigth]\] \[=2[9\times 4.5+6\times 4.5]=135\,{{m}^{2}}\]You need to login to perform this action.
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