A) 20 m
B) 30 m
C) 40 m
D) 50 m
Correct Answer: C
Solution :
Area of field = Area of \[\Delta \,ABQ+\]Area of trapezium QBCS + Area of \[\Delta \,SCD+\]Area of \[\Delta \,DRF+\] + Area of trapezium ERPF + Area of \[\Delta \,APF\] \[=\frac{1}{2}.80.40+\frac{1}{2}.80(40+x)+\frac{1}{2}x.40+\frac{1}{2}.80.x\] \[+\frac{1}{2}.80.(40+x)+\frac{1}{2}.40.40\] \[=5600+140x\] \[\therefore \] \[5600+140x=11200\] or \[x=40\,m\]You need to login to perform this action.
You will be redirected in
3 sec