A) \[\frac{100\sqrt{2}}{\pi }cm\]
B) \[\frac{50\sqrt{2}}{\pi }cm\]
C) \[\frac{100}{\pi }cm\]
D) \[50\sqrt{2}\,cm\]
Correct Answer: B
Solution :
Let r be the radius of the circle in centimeter. Then its circumference\[=2\pi r=100\] \[\therefore \] Diameter\[=2r=\frac{100}{\pi }\] The length of the largest diagonal of the square = diameter of the circle\[=2r=\frac{100}{\pi }cm\] \[\therefore \] Side of square \[=\frac{1}{\sqrt{2}}\times \] Largest diagonal \[=\frac{1}{\sqrt{2}}\times \frac{100}{\pi }=\frac{50\sqrt{2}}{\pi }cm.\]You need to login to perform this action.
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