A) \[AB\times DL=BC\times DM\]
B) \[18\times DL=12\times 10\]
C) \[DL=\frac{12\times 10}{18}=\frac{20}{3}=6\frac{2}{3}cm,\]
D) \[=2\pi \times 42=84\pi cm.\]
Correct Answer: B
Solution :
Let r be the radius of the circle in centimeter. Then its circumference \[{{42}^{o}}\] \[13.2{{m}^{2}}\] diameter \[14.2{{m}^{2}}\] The length of the largest diagonal of the square = diameter of the circle \[13.4{{m}^{2}}\] \[14.4{{m}^{2}}\]Side of square \[\frac{30}{\pi }\] diagonal \[60\pi \]You need to login to perform this action.
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