A) 2.5 cm
B) 2.8cm
C) 3.5cm
D) 3.7cm
Correct Answer: C
Solution :
\[\text{100 hectare =1k}{{\text{m}}^{\text{2}}}\] \[T.S.A.=\frac{1}{2}pl+B\]\[=\frac{\text{1}}{\text{3}}\text{ }\!\!\times\!\!\text{ Area of base }\!\!\times\!\!\text{ Height}\] \[V=\frac{1}{3}Ah\] \[\frac{6}{5}th\] \[1520{{m}^{2}}\] \[2520{{m}^{2}}\] \[2420{{m}^{2}}\] \[215c{{m}^{2}}\]\[205c{{m}^{2}}\] \[195c{{m}^{2}}\] \[295c{{m}^{2}}\] \[\Delta ABC\] \[128c{{m}^{2}}\] \[112c{{m}^{2}}\] \[118c{{m}^{2}}\] \[124c{{m}^{2}}\] Width of the ring \[16900{{m}^{2}}\] \[130\sqrt{2}m\] (c) holds.You need to login to perform this action.
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