A) 1 : 2
B) 2 : 1
C) 1 : 4
D) 4 : 1
Correct Answer: C
Solution :
\[\frac{Spindle\,\,of\,\,fset}{Lead\,\,screw\,\,speed}\] \[\frac{pitch\,\,of\,\,threads\,\,to\,\,be\,\,produceed}{Number\,\,of\,\,starts\times Pitch\,\,of\,\,threads\,\,of\,lead\,\,screw}\]\[=\frac{2}{2\times 4}=\frac{1}{4}\,\,or\,\,1:4\]You need to login to perform this action.
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