• # question_answer What is the force required to be exerted by the punch in order to shear out the blank (for a circular disc) of 20 mm diameter and 1.5 mm thickness and having a shear strength equal to 300 MPa? A) 9.0 kN              B) 18.0 kNC) 28.3 kN            D) 45.0 kN

$F=\pi dt\tau =\pi \times 20\times 1.5\times 300=28.3\,kN$