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Railways NTPC (Technical Ability) Metal Forming, Casting and Cutting Question Bank Metal Forming

  • question_answer
    What is the force required to be exerted by the punch in order to shear out the blank (for a circular disc) of 20 mm diameter and 1.5 mm thickness and having a shear strength equal to 300 MPa?

    A) 9.0 kN              

    B) 18.0 kN

    C) 28.3 kN            

    D) 45.0 kN

    Correct Answer: C

    Solution :

    \[F=\pi dt\tau =\pi \times 20\times 1.5\times 300=28.3\,kN\]


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