A) 0.5 W
B) W
C) 2 W
D) 4 W
Correct Answer: D
Solution :
Relative density of cork = 4 Therefore it will float up to \[\frac{1}{4}th\] of its height in the liquid. Centre of gravity and centre of buoyancy of cork must coincide to make it float in neutral equilibrium. Therefore, the cork must be immersed to its full height. For this purpose, downward force to be applied to cork = buoyant force on cork = 4 W.You need to login to perform this action.
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