A) \[{{H}_{2}}\]
B) NO
C) \[{{N}_{2}}O\]
D) \[{{N}_{2}}{{O}_{3}}\]
Correct Answer: B
Solution :
When dil. \[HN{{O}_{3}}\] reacts with copper, cupric nitrate is formed and nitric oxide \[(NO)\] gas is evolved. \[3Cu+8HN{{O}_{3}}\to 3Cu{{(N{{O}_{3}})}_{2}}+2NO+4{{H}_{2}}O\]You need to login to perform this action.
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