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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    When \[7.1gm\,N{{a}_{2}}S{{O}_{4}}\] (molecular mass 142) dissolves in \[100\,ml\,{{H}_{2}}O\], the molarity of the solution is [CBSE PMT 1991; MP PET 1993, 95]

    A)                 2.0 M     

    B)                 1.0 M

    C)                 0.5 M     

    D)                 0.05 M

    Correct Answer: C

    Solution :

              Molarity \[=\frac{w\times 1000}{ml\text{ wt}\text{. }\times \text{Volume }ml.}\] =\[\frac{7.1\times 1000}{142\times 100}=0.5\,M\].


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