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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    When \[6gm\] urea dissolve in \[180\,gm\,{{H}_{2}}O\]. The mole fraction of urea is                                               [CPMT 1988]

    A)                 \[\frac{10}{10.1}\]               

    B)                 \[\frac{10.1}{10}\]

    C)                 \[\frac{10.1}{0.1}\]              

    D)                 \[\frac{0.1}{10.1}\]

    Correct Answer: D

    Solution :

              Mole fraction  \[X=\frac{n}{n+N}\]\[=\frac{\frac{6}{60}}{\frac{6}{60}+\frac{180}{18}}=\frac{0.1}{10.1}\].


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