A) 0.176
B) 3.52
C) 1.78
D) 0.88
E) 17.8
Correct Answer: C
Solution :
\[{{H}_{2}}{{O}_{2}}\to {{H}_{2}}O+\frac{1}{2}{{O}_{2}}\] 1 M \[{{H}_{2}}{{O}_{2}}\]solution \[=2N=34\,gm/litre=11.2\] So Normality\[=\frac{2\times 10}{11.2}=1.75\]
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