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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    The weight of sodium carbonate required to prepare 500 ml of a semi­- normal solution is       [JIPMER 1999]

    A)                 13.25 g  

    B)                 26.5 g

    C)                 53 g       

    D)                 6.125 g

    Correct Answer: A

    Solution :

               \[N=\frac{w\times 1000}{eq.\,wt.\times \text{volume}\,\,\text{in}\,\,\text{ml}.}\] \[eq.\,wt.=\frac{106}{2}=53\]                 \[w=\frac{0.5\times 53\times 500}{1000}=13.25\].


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