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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    If we take \[44g\] of \[C{{O}_{2}}\] and \[14g\] of \[{{N}_{2}}\] what will be mole fraction of \[C{{O}_{2}}\] in the mixture             [KCET 1990]

    A)                 1/5         

    B)                 1/3

    C)                 2/3         

    D)                 ¼

    Correct Answer: C

    Solution :

              Mole fraction of CO2\[=\frac{{{n}_{C{{O}_{2}}}}}{{{n}_{C{{O}_{2}}}}+{{n}_{{{N}_{2}}}}}\]\[=\,\frac{\frac{44}{44}}{\frac{44}{44}+\frac{14}{28}}=\frac{2}{3}\].


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