A) 0.2 water + 0.8 ethanol
B) 0.4 water + 0.6 ethanol
C) 0.6 water + 0.8 ethanol
D) 0.8 water + 0.2 ethanol
Correct Answer: A
Solution :
0.2 water + 0.8 ethanol; \[{{X}_{A}}=\] mole fraction of water, \[{{X}_{B}}=\]mole fraction of ethanol \[{{X}_{A}}=\frac{{{N}_{1}}}{{{N}_{1}}+{{N}_{2}}}\], \[{{X}_{B}}=\frac{{{N}_{2}}}{{{N}_{2}}+{{N}_{1}}}\] \[\therefore \] Mole fraction of water = 0.2 and ethanol = 0.8.
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