JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    The number of molecules in 4.25 g of ammonia is approximately                                                 [CBSE PMT 2002]

    A)                 \[0.5\times {{10}^{23}}\]

    B)             \[1.5\times {{10}^{23}}\]

    C)                 \[3.5\times {{10}^{23}}\]

    D)                 \[2.5\times {{10}^{23}}\]

    Correct Answer: B

    Solution :

           \[17\,gm\,\,N{{H}_{3}}\]= 1 mole.                 Molecules of \[N{{H}_{3}}=\frac{6.02\times {{10}^{23}}\times 4.25}{17}=1.5\times {{10}^{23}}\]


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