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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    The amount of anhydrous \[N{{a}_{2}}C{{O}_{3}}\] present in 250 ml of 0.25 M solution is                                              [DPMT 2001]

    A)                 6.225 g  

    B)                 66.25 g

    C)                 6.0 g      

    D)                 6.625 g

    Correct Answer: D

    Solution :

                    \[M=\frac{w}{m\times V(l)}\] ; \[0.25=\frac{w}{106\times 0.25}\];\[w=6.625\] gm


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