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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    The amount of \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] (eq. wt. 49.04) required to prepare 100 ml of its 0.05 N solution is    [JIPMER 2002]

    A)                 2.9424 g               

    B)                 0.4904 g

    C)                 1.4712 g               

    D)                 0.2452 g

    Correct Answer: D

    Solution :

                    \[W=\frac{N\times eq.wt.\times V(ml)}{1000}=\frac{0.05\times 49.04\times 100}{1000}\]\[=0.2452.\]


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