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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    A solution of \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\,\{d=1.253\,gm/ml\}\]contain 22% salt by weight. The molarity, normality and molality of the solution is                                              [MP PET 2004]

    A)                 0.805 M, 4.83 N, 0.825 M

    B)                 0.825 M, 48.3 N, 0.805 M

    C)                 4.83 M, 4.83 N, 4.83 M      

    D)             None

    Correct Answer: A

    Solution :

               Molarity \[=\frac{%\times 10\times d}{GMM}\] \[=\frac{22\times 10\times 1.253}{342}=0.805M\].                    Normality \[=\frac{%\times 10\times d}{GEM}\] \[=\frac{22\times 10\times 1.253}{342/6}=4.83N\]                                 Molality \[=\frac{22\times 1000}{342(100-22)}=0.825m\]


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