A) 8 gm of \[KOH\]/ litre
B) \[N\] phosphoric acid
C) 6 gm of \[NaOH\]/ 100 ml
D) \[0.5M\,{{H}_{2}}S{{O}_{4}}\]
Correct Answer: C
Solution :
\[N=\frac{6\times 1000}{40\times 100}=1.5\,N\] It is show highest normality than others.
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