A) 0.02 M
B) 0.01 M
C) 0.001 M
D) 0.1 M (Avogadro constant, \[{{N}_{A}}=6.02\times {{10}^{23}}mo{{l}^{-1}})\]
Correct Answer: B
Solution :
Mole of urea \[=\frac{6.02\times {{10}^{20}}}{6.02\times {{10}^{23}}}={{10}^{-3}}\] moles Conc. of solution (in molarity)You need to login to perform this action.
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