A) 6 N
B) 2 N
C) 4 N
D) 8 N
Correct Answer: B
Solution :
Mole of \[HCl=\frac{1.2046\times {{10}^{24}}}{6.023\times {{10}^{23}}}=2\,mole\] Normality = molarity\[\times \]basidity or acicity \[=2\times 1=2N\]You need to login to perform this action.
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