A) 0.1
B) 0.2
C) 0.3
D) 0.01
E) 0.0196
Correct Answer: E
Solution :
5.85 g NaCl = \[\frac{5.85}{58.5}\,mole=0.1\,\,mol\] 90 g \[{{H}_{2}}O=\frac{90}{18}\,moles=5\,\,moles\] mole fraction of NaCl = \[\frac{0.1}{5+0.1}\approx 0.0196\].You need to login to perform this action.
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