A) 4 g
B) 6 g
C) 40 g
D) 60 g
Correct Answer: B
Solution :
1500 \[c{{m}^{3}}\] of 0.1 N HCl have number of gm equivalence \[=\frac{{{N}_{1}}\times {{V}_{1}}}{1000}=\frac{1500\times 0.1}{1000}=0.15\] \[\therefore 0.15\,gm.\] equivalent of NaOH \[=0.15\times 40=6\,gm.\]You need to login to perform this action.
You will be redirected in
3 sec