A) \[\frac{77}{68}\]
B) \[\frac{68}{77}\]
C) \[\frac{20}{80}\]
D) \[\frac{80}{20}\]
Correct Answer: B
Solution :
Mole fraction of \[{{H}_{2}}O\] = \[\frac{\frac{80}{18}}{\frac{80}{18}+\frac{20}{24}}\] = \[\frac{68}{77}\].
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