A) \[\frac{\text{No}\text{. of moles of solute}}{\text{Volume of solution in litre}}\]
B) \[\frac{\text{No}\text{. of gram equivalent of solute}}{\text{Volume of solution in litre }}\]
C) \[\frac{\text{No}\text{. of moles of solute}}{\text{Mass of solvent in kg}}\]
D) None of these
Correct Answer: B
Solution :
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