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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    0.5 M of \[{{H}_{2}}S{{O}_{4}}\] is diluted from 1 litre to 10 litre, normality of resulting solution is    [AFMC 2005]

    A)                 1 N         

    B)                 0.1 N

    C)                 10 N      

    D)                 11 N

    Correct Answer: B

    Solution :

           Molarity of \[{{H}_{2}}S{{O}_{4}}=0.5\] Normality of \[{{H}_{2}}S{{O}_{4}}\,\,({{N}_{1}})=0.5\times 2=1\] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\]                                 \[1\times 1={{N}_{2}}\times 10\] or \[{{N}_{2}}=\frac{1}{10}=0.1N.\]


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