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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    The molality of 90% \[{{H}_{2}}S{{O}_{4}}\] solution is                 [density=1.8 gm/ml]            [MP PMT 2004]

    A)                 1.8         

    B)                 48.4

    C)                 9.18       

    D)                 94.6

    Correct Answer: C

    Solution :

               The density of solution \[=1.8\,gm/ml\]               Weight of one litre of solution \[=1800\,gm\]                    \[\therefore \] Weight of \[{{H}_{2}}S{{O}_{4}}\] in the solution\[=\frac{1800\times 90}{100}\]=162gm                    \[\therefore \] Weight of solvent \[=1800-1620=180\,gm\]                                 \[\therefore \] Molality \[=\frac{1620}{98}\times \frac{100}{180}=9.18\]


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