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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    When \[1.80gm\] glucose dissolve in \[90\,gm\] of \[{{H}_{2}}O\], the mole fraction of glucose is           [AFMC 2000]

    A)                 0.00399

    B)                 0.00199

    C)                 0.0199  

    D)                 0.998

    Correct Answer: B

    Solution :

           Mole fraction of glucose = \[\frac{n}{n+N}\]                 = \[\frac{0.01}{0.01+5}=0.00199\]


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