2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Solutions / विलयन

JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Method of expressing concentration of solution

  • question_answer
    The number of moles of \[S{{O}_{2}}C{{l}_{2}}\] in \[13.5gm\] is            [CPMT 1994]

    A)                 0.1         

    B)                 0.2

    C)                 0.3         

    D)                 0.4

    Correct Answer: A

    Solution :

           Gram molecule of \[S{{O}_{2}}C{{l}_{2}}\] = 135                  \[n=\frac{w}{m}=\frac{13.5}{135}=0.1\].


You need to login to perform this action.
You will be redirected in 3 sec spinner