A) 90%
B) 92%
C) 95%
D) 98%
Correct Answer: D
Solution :
\[{{S}_{p}}=K\sqrt{\frac{p(1-p)}{N}}\] \[K=2\] for 95% confidence level \[S\times 0.04=2\sqrt{\frac{0.04\times 0.96}{100}}=0.0392\] \[S=0.98\,\,or\,\,98%\]You need to login to perform this action.
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