JEE Main & Advanced Physics Ray Optics Question Bank Microscope and Telescope

  • question_answer
    A telescope has an objective of focal length 50 cm and an eye piece of focal length 5 cm. The least distance of distinct vision is 25 cm. The telescope is focused for distinct vision on a scale 200 cm away. The separation between the objective and the eye-piece is                                              [Kerala PET 2002]

    A)            75 \[cm\]                               

    B)            60 \[cm\]

    C)            71 \[cm\]                               

    D)            74 \[cm\]

    Correct Answer: C

    Solution :

                       \[{{f}_{o}}=50\ cm,\]\[{{f}_{e}}=5\ cm,\]\[D=25\ cm\] and \[{{u}_{o}}=200\ cm.\]                    Separation between the objective and the eye lens is            \[L=\frac{{{u}_{o}}{{f}_{o}}}{({{u}_{o}}-{{f}_{o}})}+\frac{{{f}_{e}}D}{({{f}_{e}}+D)}\]\[=\frac{200\times 50}{(200-50)}+\frac{5\times 25}{(5+25)}=71\ cm\]


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