JEE Main & Advanced Physics Ray Optics Question Bank Microscope and Telescope

  • question_answer
    The magnifying power of a microscope with an objective of 5 mm focal length is 400. The length of its tube is 20 cm. Then the focal length of the eye-piece is                   [MP PMT 1991]

    A)            200 cm                                    

    B)            160 cm  

    C)            2.5 cm                                     

    D)             0.1 cm  

    Correct Answer: C

    Solution :

               If nothing is said then it is considered that final image is formed at infinite and \[{{m}_{\infty }}=\frac{({{L}_{\infty }}-{{f}_{o}}-{{f}_{e}})\ .D}{{{f}_{o}}{{f}_{e}}}\underline{\tilde{\ }}\frac{LD}{{{f}_{0}}{{f}_{e}}}\]            \[\Rightarrow 400=\frac{20\times 25}{0.5\times {{f}_{e}}}\Rightarrow {{f}_{e}}=2.5\ cm.\]


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