A) 21.25 cm and 16
B) 75 cm and 20
C) 75 cm and 16
D) 8.5 cm and 21.25
Correct Answer: C
Solution :
\[{{f}_{o}}=\frac{1}{1.25}=0.8\,m\] and \[{{f}_{e}}=\frac{1}{-20}=-\,0.05\,m\] \ \[|{{L}_{\infty }}|\,=\,|{{f}_{o}}|\,-\,|{{f}_{e}}|\,=0.8-0.05=0.75\,m=75\,cm\] and \[|{{m}_{\infty }}|\,=\frac{{{f}_{o}}}{{{f}_{e}}}=\frac{0.8}{0.05}=16\]You need to login to perform this action.
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