A) 0.7 cm
B) 1.4 cm
C) 2.8 cm
D) Zero (i.e. point image)
Correct Answer: C
Solution :
\[\theta =\frac{AB}{{{10}^{11}}}=\frac{{A}'{B}'}{2}\Rightarrow {A}'{B}'=\frac{2\times 1.4\times {{10}^{9}}}{{{10}^{11}}}=2.8\ cm\]You need to login to perform this action.
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